1989 Virginia Slims of Chicago – Doubles

Doubles
1989 Virginia Slims of Chicago
Champions	Larisa Savchenko Natasha Zvereva
Runners-up	Jana Novotná Helena Suková
Score	6–3, 2–6, 6–3
Draw	16
Seeds	4

Lori McNeil and Betsy Nagelsen were the defending champions, but both players competed this year with different partners. McNeil teamed up with Hana Mandlíková and were forced to withdraw in the quarterfinals, while Nagelsen teamed up with Mary Joe Fernández and lost in the semifinals to Larisa Savchenko and Natasha Zvereva

Savchenko and Zvereva won the title by defeating Jana Novotná and Helena Suková 6–3, 2–6, 6–3 in the final.^[1]

	First round							Quarterfinals							Semifinals							Final
	1	J Novotná H Suková	6	4	6
		E Burgin R Fairbank	3	6	2			1	J Novotná H Suková	w/o
		R Baranski D Faber	6	4	2				H Mandlíková L McNeil
		H Mandlíková L McNeil	3	6	6										1	J Novotná H Suková	7	6
	3	K Adams Z Garrison	6	6												B Schultz P Shriver	5	1
		S Amiach C Reynolds	4	3				3	K Adams Z Garrison	5	5
		A Frazier M Werdel	3	0					B Schultz P Shriver	7	7
		B Schultz P Shriver	6	6																		1	J Novotná H Suková	3	6	3
		A Henricksson A Smith	2	4																		2	L Savchenko N Zvereva	6	2	6
		B Bunge E Pfaff	6	6					B Bunge E Pfaff	4	1
		K Gompert P Vásquez	3	1				4	MJ Fernández B Nagelsen	6	6
	4	MJ Fernández B Nagelsen	6	6											4	MJ Fernández B Nagelsen	2	2
		R Casals J Smoller	1	3											2	L Savchenko N Zvereva	6	6
		M Lindström H Ludloff	6	6					M Lindström H Ludloff	6	5	3
		G Magers K Rinaldi	63	1				2	L Savchenko N Zvereva	4	7	6
	2	L Savchenko N Zvereva	77	6

• Official results archive (ITF)
• Official results archive (WTA)